Question

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
A(n) = 1+(n-1)(-4.1)

Answer 1

Hi ,

Given rule

A ( n ) = 1 + ( n - 1 ) ( - 4.1 )

1 ) let n = 1

First term = A ( 1 )

= 1 + ( 1 - 1 ) ( - 4.1 )

= 1 + 0

= 1

A ( 1 ) = 1

2 ) if n = 4

Fourth term = A ( 4 )

= 1 + ( 4 -1 ) ( - 4.1 )

= 1 + 3 × ( - 4.1 )

= 1 - 12. 3

= - 11.3

A ( 4 ) = - 11.3

3 ) let n = 10

Tenth term = A ( 10 )

= 1 + ( 10 - 1 ) ( - 4.1 )

= 1 + 9 × ( - 4.1 )

= 1 - 36.9

= - 35.9

A ( 10 ) = - 35.9

Therefore,

First term = 1 ,

Fourth term = -11.3

Tenth term = - 35.9

I hope this will usful to you.

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