Find the first negative term of ap 120, 117, 114
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HELLO DEAR,
.
121,117,113......
a=121. d=-4
For a(n) be negative
a(n)<0
a+(n-1)d <0
121+(n-1)*(4)<0
For ans be negative
(n-1)(-4)>121
4n >(125)
n >125/4
n >31.25
n=32
the 31st term is the negative term
a(n)=a+(n-1)d
a(n)=121+(32-1)-4
a(n)=121+31*-4
a(n)=121-124
a (n)=-3
I HOPE ITS HELP YOU DEAR,
THANKS
.
121,117,113......
a=121. d=-4
For a(n) be negative
a(n)<0
a+(n-1)d <0
121+(n-1)*(4)<0
For ans be negative
(n-1)(-4)>121
4n >(125)
n >125/4
n >31.25
n=32
the 31st term is the negative term
a(n)=a+(n-1)d
a(n)=121+(32-1)-4
a(n)=121+31*-4
a(n)=121-124
a (n)=-3
I HOPE ITS HELP YOU DEAR,
THANKS
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