Question

Find the first negative term of AP 122,116,110...​

Answer 1

Step-by-step explanation:

AP is 122,116,110.....

The nth term of an AP is given by

a

n

=a+(n−1)d

here, a=122

d=116−122=−6

Let the nth term of the AP be its first negative term

a

n

<0

a+(n−1)d<0

122+(n−1)(−6)<0

122−6n+6<0

128<6n

6n>128

n>

6

128

n>21.33

Since the first negative term is greater than 21.22

So, it is 22nd term.