Find the first negative term of AP 129,120, ,
111,102,...
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AP sequence is
129, 120 ,111,102
Let's find a , d from this sequence
a = 129
d = - 9
So, to find 1st -ve term first we will find the place of 0 in this AP
an = a + (n-1) d
0 = 129 +( n-1) -9
0 = 129 -9n +9
0 = 138 -9n
-138 = -9n
138/9 = n
n = 15.33
So the place next to the place of 0 is the place of-ve term
1st -ve term place = 16
-ve term = 129 +( 16 -1)-9
= 129 -135 = -6
So 1st -ve term is -6
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