Question

Find the first negative term of AP 129,120, ,
111,102,...
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Answer 1

Answer:

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Answer 2

Answer:

AP sequence is

129, 120 ,111,102

Let's find a , d from this sequence

a = 129

d = - 9

So, to find 1st -ve term first we will find the place of 0 in this AP

an = a + (n-1) d

0 = 129 +( n-1) -9

0 = 129 -9n +9

0 = 138 -9n

-138 = -9n

138/9 = n

n = 15.33

So the place next to the place of 0 is the place of-ve term

1st -ve term place = 16

-ve term = 129 +( 16 -1)-9

= 129 -135 = -6

So 1st -ve term is -6