Find the first quadrant area bounded by the curves: y = arctanx, y = and 4 π x = 0. Q
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Given: The correct boundaries are y = arc tan x, y=π/4 and x=0.
To find: Find first quadrant area bounded by the curves given.
Solution :
- Now we have given the curves y = arc tan x, y=π/4 and x=0.
- So integrating y = tan^-1 x , where limits are:
upper limit is y₂ = π/4 and lower limit is y₁ = 0
- The area bounded is:
∫ tanx dx (here upper limit is y₂ = π/4 and lower limit is y₁ = 0)
ln | sec x | (here upper limit is y₂ = π/4 and lower limit is y₁ = 0)
ln(sec π/4) - ln(sec 0)
ln(√2) - ln(1)
ln(√2)
0.346
Answer:
So the area bounded is 0.346 sq. units.
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