Question

Find the first six terms of the sequence. A1 = 1, an = 4 an-1

Answer 1

Answer:

Step-by-step explanation:

1. a₁ = 1

an = 4.(an-1)

a₁ = 4.(a₀)

1 = 4(a₀)

a₀ = 1/4

(or)

a₁ = 1

an = 4

an-1 =

1, 4, 8, 14, 22, 32, ………

Answer 2

The first six terms of the sequence are 1,4,16,64,256,1024.

Step-by-step explanation:

Given : Sequence with  $a_1=1, a_n=4\times a_{n-1}$

To find : The first six terms of the sequence ?

Solution :

Now we have, $a_n=4\times a_{n-1}$

Put different values of n,

When n=2,

$a_2=4\times a_{1}$

$a_2=4\times1$

$a_2=4$

When n=3,

$a_3=4\times a_{2}$

$a_3=4\times4$

$a_3=16$

When n=4,

$a_4=4\times a_{3}$

$a_4=4\times16$

$a_4=64$

When n=5,

$a_5=4\times a_{4}$

$a_5=4\times64$

$a_5=256$

When n=6,

$a_6=4\times a_{5}$

$a_6=4\times256$

$a_6=1024$

The first six terms of the sequence are 1,4,16,64,256,1024.

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