find the first term and the nth term of an AP whose 6th term is12 and 8th term is 21
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Answer:
tn= (a+(n-1) d)
t6= a+(6-1)
a+5d=12 (1)
t8= a+(8-1)d (2)
a+7d=21
subtracting (3)-(1)
2d=10
d=5 a+5d=12
+2=a+(2-1)d a+25=12
a=12-25
=-13+5=-8
tn=a+(n-1)d
=-13+(n-1)5
= -13+5n-5
5n-18
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