Question

Find the first term, if k + 2, 4k - 6 and 3k - 2 are the three consecutive terms of an
A.P.
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Answer 1

Answer:

the value of k =5

because in AP 2b=a+c

2(4k+3)=3k+2+6k-1

8k+6=9k+1

8k-9k=1-6

-k=-5

k=5 (answer)