Question

find the first term of 15th term of an ap​

Answer 1

Answer:

$a_{n} = a +(n-1)d$

$a_{15} = a+ (15-1 )d\\ a_{15} = a+14d$

Step-by-step explanation:

mark it as brainliest answer

Answer 2

To find:-

• 15th term of ap

Solution:-

$\sf \longrightarrow \: a_{n} = a + (n - 1)d \\ \sf \ \longrightarrow \: a_{15} = a + (15 - 1)d \\ \sf \longrightarrow\: a_{15} = a + (14)d \\ \sf \longrightarrow \: \boxed{ \boxed{ \red{ \tt{a_{15} = a + 14d}}}}$

Therefore, the value of 15th term of ap is a+14d.

More details:-

• AP is a form of integers in which the difference between two consecutive terms is constant.

• General formula for AP: a, a+d, a+2d, a+3d.

• Sum of nth terms: $\sf S_{n}=\dfrac{n}{2}\{2a+(n-1)d\}$

• Sum of first n natural no.

$\sf S_{n}=\dfrac{n(n+1)}{2}$