Question

Find the first term of an AP, whose second term is 14 and common difference is 14.

Answer 1

Answer:

The A.P is given by a1,a1+d,a1+2d,......

so the first term is a1, the second term is given by a2= a1+d

Now, a2 = 14 and d =14

then a2 = a1+d

14 = a1 + 14

∴ the first term a1 = 0

Step-by-step explanation:

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Answer 2

Answer:

The ans of the ques would be zero.

Step-by-step explanation:

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