Question

find the first term of G. P. Whose second term is 2 and sum to infinity is 8.

Answer 1

$x \div (1 - y) = 8$
where x= first term of g. p
and. y= common difference
$x \times y = 2$
therefore,
$y = 2 \div x$
$x {}^{2} \div( x - 2) = 8$
$(x - 4) { }^{2} = 0 \\ x = 4$