Question

Find the first term of the sequence whose 12th term is 8,388,608 and its common ratio is 4.​

Answer 1

a=2

Step-by-step explanation:

an=ar^n-1

a12=a4^12-1

8,388,608=a4^11

8,388,608=a(4194304)

8,388,608/4194304=a(4194304)/4194304

2=a

Therefore, the first term of the geometric sequence is 2.