. Find the first three terms and the seventh term of the A.P. whose nth term is 3n-2.
Answers
Answered by
1
Answer:
nth term is equal to. a+(n-1)d
a+(n-1)d= 3n + 5
On opening bracket on l.h.s.
dn + (a-d)= 3n + 5.
On comparing both the sides.
dn= 3n therefore d=3.
Also a-d = 5
a-3 =5
a= 8
Seventh term = 8+ (7–1)×3
Seventh term = 8+18
The answer is 26.
Answered by
0
Answer:
Step-by-step explanation:
To find out the first three terms of 3n - 2 substitute 1 ,2 and 3 into the equation.
3(1)-2=1
3(2)-2=4
3(3)-2=7
As you can see the sequence goes up in 3s.. 1 ,4, 7
To find AP
a_{n}=a_{1}+(n-1)d
a_n = the nᵗʰ term in the sequence
a_1 = the first term in the sequence
d = the common difference between terms
a3= a1+ 2d
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