Question

find the first three terms of a sequence whose nth term is given by tn=3n+1

Answer 1

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$tn = 3n + 1$

$put \: n = 1$

$t(1) = 3 \times 1 + 1 = 4$

$n = 2$

$t(2) = 3 \times 2 + 1 = 7$

$n = 3$

$t(3) = 3 \times 3 + 1 = 10$

Answer 2

Answer:

The first three terms of the sequence = 3,7,10

Step-by-step explanation:

Given,

The nth term of a sequence  $t_n$ = 3n+1

Required to find,

The first 3 terms of the sequence

Solution

The first term = $t_1$ = 3×1 +1 = 3 +1 = 4

The second term = $t_2$ = 3×2 +1 = 6+1 = 7

The third term = $t_3$ =  3×3 +1 = 9+1 = 10

∴The first three terms of the sequence = 3,7,10

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