Find the first three terms of a sequence whose nth term is 2n-1 - 4n
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tn=2n-1-4n. when n=1, t1=2(1)-1-4(1) =2-1-4=-3. #when n=2. t2=2(2)-1-4(2) -=4-1-8 :n=-5. #when n=3. t3=2(3)-1-4(3) , =6-1-12: n=-7. therefore the first three term
paranuel42:
the first three terms of the sequence =-3,-5,-7. if it helps (mark as brainliest)
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