Question

find the first three terms of an increasing A.P,where in the sum of the first three term is 42 and whose products is 2618 Please reply fast.

Answer 1

Let the three terms be a-d,+a,a+d.

ATQ

Sum of the first three term is 42

Therefore

a-d+a+a+d=42

3a=42

a=14

ATQ

products is 2618

Therefore

(a-d)(a+d)a=2618

(a^2-d^2)14=2618

a^2-d^2=187

-d^2=-9

d=3

Numbers=a-d=14-3=11

a=14

a+d=14+3=17

Answer 2

Step-by-step explanation:

hope it helps you ❤

step by step explanation

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