Question

Find the first three terms of the sequence below. T n = n 2 − 2 n − 6

Answer 1

Answer:

$T_{1} =-7,\ T_{2}=-6,\ T_{3}=-3$

Step-by-step explanation:

Given $T_{n} =n^{2} -2n-6$

to find the first three terms just put the values $1,2,3$ to $n$.

then

$T_{1} =1^{2} -2(1)-6=1-2-6=-7$

$T_{2} =2^{2}-2(2)-6=4-4-6=-6$   , and

$T_{3}=3^{2} -2(3)-6=9-6-6=-3$

hence the answer

thank you