Find the first Tow terms of the seqence Sn=n2(n+1)
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S1 = 2(1+1)
=2×2
=4
a=4
S2 =2×2(2+1)
=4×3
=12
n/2(2a+(n-1)d)=12
2/2(8+d)=12
8+d=12
d=4
a2 =a+d
=4+4
8
first two terms are 4 and 8
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