Find the first two terms of sequence for which sequence of Sn is given as n²(n+1)
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Step-by-step explanation:
Sn = n²(n+1)
∴ If we put n = 1 then ,
S1 = 1² ( 1 + 1 )
∴ S1 = 2
ALSO S1 = a1 = first term of the AP = 2
∴ first term of AP is 2
Again if we put n = 2 then
S2 = 2² ( 2 + 1 ) = 12
∵ a2 = second term of AP is = S2 - S1
∴ a2 = second term of AP is = 12 - 2 = 10
∴ the AP is 2 , 12 , ..............
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