find the first two terms of the sequence tn=3n-4
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Answered by
28
Hi ,
Given sequence tn = 3n - 4
i ) if n = 1 ,
First term = t1 = 3 × 1 - 4
= 3 - 4
t1 = - 1
ii ) if n = 2 ,
Second terms = t2 = 3 × 2 - 4
= 6 - 4
t2 = 2
Therefore ,
Required two terms are -1 , 2
I hope this helps you.
: )
Given sequence tn = 3n - 4
i ) if n = 1 ,
First term = t1 = 3 × 1 - 4
= 3 - 4
t1 = - 1
ii ) if n = 2 ,
Second terms = t2 = 3 × 2 - 4
= 6 - 4
t2 = 2
Therefore ,
Required two terms are -1 , 2
I hope this helps you.
: )
Answered by
9
Heya !!!
Tn = 3N -4
T1 = 3 × 1 -4 = 3-4
=> -1
And,
T2 = 3 × 2 -4
=> 6-4
=> 2.
Hence,
First two terms are -1 and 2.
HOPE IT WILL HELP YOU........ :-)
Tn = 3N -4
T1 = 3 × 1 -4 = 3-4
=> -1
And,
T2 = 3 × 2 -4
=> 6-4
=> 2.
Hence,
First two terms are -1 and 2.
HOPE IT WILL HELP YOU........ :-)
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