Math, asked by haopuzou, 1 year ago

Find the five solutions of 3x+5y= 15


Anuragkumar2626: zero

Answers

Answered by Nidhi864
29
You get to pick any points you want so make it easy on yourself. Because this is in standard form, (Ax+By=C), the x and y intercepts are easiest to solve for.
:
Let x=0 and solve for y (y-intercept)
3(0)+5y=15
0+5y=15
5y=15
5y/5=15/5
y=3
One solution is: (0,3)
:
Let y=0 and solve for x. (x intercept)
3x+5(0)=15
3x+0=15
3x=15
3x/3=15/3
x=5
Your second solution is (5,0)
:
The next two points, I'm going to pick are letting x=-10 and x=10. I know that they will work out to be whole numbers, it takes practice to find the easiest points.
Let x=-10 and solve for y.
3(-10)+5y=15
-30+5y=15
30-30+5y=15+30
5y=45
5y/5=45/5
y=9
Your third solution is: (-10,9)
:
Let x=10 and solve for y.
3(10)+5y=15
30+5y=15
-30+30+5y=-30+15
5y=-15
5y/5=-15/5
y=-3
Your fourth solution is: (10,-3)
:
Can you think of any others??? (Pick x's that are divisible by 5 to get whole numbers.)
Happy Calculating!!!!

Answered by nitishkhokhar6
3

Answer:

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Step-by-step explanation:

You get to pick any points you want so make it easy on yourself. Because this is in standard form, (Ax+By=C), the x and y intercepts are easiest to solve for.

:

Let x=0 and solve for y (y-intercept)

3(0)+5y=15

0+5y=15

5y=15

5y/5=15/5

y=3

One solution is: (0,3)

:

Let y=0 and solve for x. (x intercept)

3x+5(0)=15

3x+0=15

3x=15

3x/3=15/3

x=5

Your second solution is (5,0)

:

The next two points, I'm going to pick are letting x=-10 and x=10. I know that they will work out to be whole numbers, it takes practice to find the easiest points.

Let x=-10 and solve for y.

3(-10)+5y=15

-30+5y=15

30-30+5y=15+30

5y=45

5y/5=45/5

y=9

Your third solution is: (-10,9)

:

Let x=10 and solve for y.

3(10)+5y=15

30+5y=15

-30+30+5y=-30+15

5y=-15

5y/5=-15/5

y=-3

Your fourth solution is: (10,-3)

:

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