Question

Find the five terms of arithmetic progressions whose sumi 121/2 and first and last term ratio is 2:3

Answer 1

Explanation:Let first and last term be 2x and 3x.

Sum =n/2 *[a +l]

121/2=n/2*5x

121=n * 5x

121/n =5x

Now put the value of n which you have not written and you will get the value of x

Put it .

You will get 1st term and last term

Answer 2

Answer:

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