Find the focal length and nature of lens which should be placed in contact with a lens of focal length 10 cm so that the power of the combination becomes 5D.
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power (P2) of length 10 cm focal length = 100/10=10D
let the power of the lens =P1
total powers of combination = P1+P2
5D=P1+100
P1=5D
focal length = -1/5 = -0.2 m
= -20 cm
power of the lens is negative so the given lens is concave lens
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