Question

Find the focal length and nature of the lens which should be placed in contact with the lens of focal length 10cm

Answer 1

Answer:

Power(P2) of lens with 10 cm focal length = 10010=10D

Power(P2) of lens with 10 cm focal length = 10010=10DLet Power of the lens is P1

Power(P2) of lens with 10 cm focal length = 10010=10DLet Power of the lens is P1Total power of combination = P1 +P2

Power(P2) of lens with 10 cm focal length = 10010=10DLet Power of the lens is P1Total power of combination = P1 +P25D= P1 + 10D

Power(P2) of lens with 10 cm focal length = 10010=10DLet Power of the lens is P1Total power of combination = P1 +P25D= P1 + 10DP1 = -5D

Power(P2) of lens with 10 cm focal length = 10010=10DLet Power of the lens is P1Total power of combination = P1 +P25D= P1 + 10DP1 = -5Dfocal length = −15=−0.2m⇒−20 cm

____________♦

@Hopeless