Find the focal length and power of convex lens which,when put in contact with a concave lens of focal length 25cm forms a real image 5 times the size of an object placed 20cm from the combination
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Magnification = 5
Magnification = image distance / object distance
5 = i / 20
Image distance = 20 × 5 = 100
Lens formula :
1/F = 1/u + 1/v
1/F = > where F is the combined focal length.
1/F = 1/20 + 1/100
1/F = (5 + 1) /100
1/F = 6/100
Let the focal length of the first lens be f₁ and the lens of the second lens be f₂.
f₁ = 25 cm
1/F = 1/f₁ + 1/f₂
6/100 = 1/25 + 1/f₂
6/100 - 1/25 = 1/f₂
(6 - 4) / 100 = 1/f₂
2/100 = 1/f₂
1/50 = 1/f₂
f₂ = 50 cm
Power = 1/focal length
Power = 1/50 = 0.02
Answer :
Focal length = 50cm
Power = 0.02
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