Find the focal length of a lens whose power is -3.5D. A lens of power +o.5 is used for
correction. Find the focal length of the combination of the lens.
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Answer:
Focal length of the combination of lens = - 0.333m
Explanation:
Power of first lens P₁ = - 3.5 D
Power of correcting lens P₂ = = 0.5 D
Total power of lens combination = P = P₁ + P₂
= - 3.5 + 0.5
= - 3 D
Focal length of combination f = 1/P
= - 1/3 m
= - 0.33 m
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