Question

Find the following 3t²+4t+1

Answer 1

Answer:

t=-1/3 or -1

Step-by-step explanation:

3t² +4t+1=0

3t²+3t+t+1=0

3t(t+1)    1(t+1) =0

(3t+1)   (t+1)  =0

t=-1/3

t=-1

Answer 2

Step-by-step explanation:

• $(4 {t}^{2} + 4t + 1) - {t}^{2}$
• $({2t + 1})^{2} - ({t})^{2}$
• $(2t + 1 + t)(2t + 1 - t)$
• $(3t + 1)(t + 1)$