Question

find the following by trail and Error method
( i ) 7m-2=12
( ii )4p+8=16
(iii)6a=16
(iv)S/7=2/16​

Answer 1

Answer:

$1) \: 7m - 2 = 12 \\ \\ = > 7m = 12 + 2 \\ \\ = > 7m = 14 \\ \\ = > m = \frac{14}{7} \\ \\ = > m = 2$

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$2) \: 4p + 8 = 16 \\ \\ = > 4p = 16 - 8 \\ \\ = > 4p = 8 \\ \\ = > p = \frac{8}{4} \\ \\ = > p = 2$

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$3) \: 6a = 16 \\ \\ = > a = \frac{16}{6} \\ \\ = > a = \frac{8}{3}$

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$4) \: \frac{s}{7} = \frac{2}{16} \\ \\ = > 16s = 14 \\ \\ = > s = \frac{14}{16} \\ \\ = > s = \frac{7}{8}$

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