find the following by using identity 1
a. (2x+5)^2
b. (0.2x+1.5y)^2
please solve in full method do it fast it's urgent
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Answered by
6
(2x+5)^2
(a+b)^2=a^2+2ab+b^2
a=2x,b=5
(2x+5)^2=(2x)^2+2 (2x)(5)+(5)^2
=4x^2+20x+25
(0.2x+1.5y)^2
(a+b)^2=a^2+2ab+b^2
a=0.2x,b=1.5y
(0.2x+1.5y)^2
=(0.2x)^2+2 (0.2x)(1.5y)+(1.5y)^2
=0.04x^2+0.60xy+3.0y^2
(a+b)^2=a^2+2ab+b^2
a=2x,b=5
(2x+5)^2=(2x)^2+2 (2x)(5)+(5)^2
=4x^2+20x+25
(0.2x+1.5y)^2
(a+b)^2=a^2+2ab+b^2
a=0.2x,b=1.5y
(0.2x+1.5y)^2
=(0.2x)^2+2 (0.2x)(1.5y)+(1.5y)^2
=0.04x^2+0.60xy+3.0y^2
Answered by
5
Answer:
This is a answer
= (8x+3y) square
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