Question

find the following by using identity-1 ..qno. i (8x+3y)square please give correct answer I will mark as brainliest and thank your 4 answers​

Answer 1

Step-by-step explanation:

${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

${(8x + 3y)}^{2} = {8x}^{2} +2 \times 8x \times 3y + {3y}^{2}$

${64x}^{2} + 48xy + {9y}^{2}$

$\mathfrak\red {hope \: this \: helps}$

Answer 2

$\star\:\:\bf\large\underline\blue{Question:-}$

• Find the value of $(8x+3y)^{2}$ using identity.

$\star\:\:\bf\large\underline\blue{Solution:-}$

Before we start, we have to know the identity to be used while solving this problem. Here is the identity.

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$

Now, we will solve the problem.

${(8x + 3y)}^{2}$

$= {(8x)}^{2} + {(3y)}^{2} + 2 \times 8x \times 3y$

$= 64 {x}^{2} + 9 {y}^{2} + 48xy$

$\star\:\:\bf\large\underline\blue{Answer:-}$

• ${(8x + 3y)}^{2} = 64 {x}^{2} + 48xy + 9 {y}^{2}$