Question

find the following from figure

Answer 1

a)Given, C1 = 19.60 μF and C2 =13.60 μF.Let the equivalent capacitance of the capacitors 6.00 μFand C2 = 13.60 μF is C’.

Therefore, C' = 6.00 + C2 = 6.00 + 13.60 = 19.60 μF .

The capacitors, C’’, of C1,C' and C1 are inseries.

Therefore, the equivalent capacitanceas per series capacitor formula: (1/C'') = (1/C1) + (1/C') + (1/C1) C1 = 19.60 μF .

b) The charge on each capacitoron the right 19.60 μF capacitor_____μC.

Formula is Q=CV , where Q= charge in coulomb and V = Voltage and C is the capacitance.

Charge on C1 , 19.6 μF= 19.6x9=176.4Coulomb.

Charge on 13.6 μF = 13.6x 9=122.4 Coulomb.

Charge on 6 μF= 6x9=54coulomb