find the following hcf of 12,30,54
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12=2×2×3•30=2×3×5•54=2×3×3×3•hcf=6
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12=2×2×3
30=2×3×5
54=2×3×3×5
common in all is 2×3
so the HCF=6
30=2×3×5
54=2×3×3×5
common in all is 2×3
so the HCF=6
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