Find the following integrals:
1. x sin(1+x²) dx
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Answer:
-cos(1+ x^{2} ) /2 + c
Explanation:
let t= 1+x^{2}
dt/dx = 2x
dt/2 = x.dx
∫ x.sin(t).dx
∫sint.dt/2
1/2∫sin(t).dt
by integration
-cos(t)/2 + c ,put value of t
hence , -cos(1+x^{2}) +c ans
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