Question

find the following product: (2x+3)(3x-y)(4x+1)​

Answer 1

Answer:

Step-by-step explanation:

(2x+3)(3x-y)(4x+1)​

=> [ 2x(3x-y) +3(3x-y) ](4x+1)

=> [6$x^{2}$-2xy + 9$x^{2}$-3y](4x+1)

=> [15$x^{2}$-2xy-3y](4x+1)

=> [$(3x)^{2}$-2xy-3y](4x+1)

=> 4x [$(3x)^{2}$-2xy-3y] + 1[$(3x)^{2}$-2xy-3y]

=> 4x$(3x)^{2}$ - (4x) × (2xy) - 4x × 3y + $(3x)^{2}$-2xy-3y

=> 12x^3 - 6xy - 12xy + $(3x)^{2}$-2xy-3y

=> 12x^3 - 6xy - 12xy -2xy + $(3x)^{2}$-3y

=>12x^3 - 20xy + $(3x)^{2}$-3y

thats the answer

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