Question

find the following product and verify the result , for x=-1,y=2 .
(x^2y^2-2) (1-x^2y^2)​

Answer 1

Step-by-step explanation:

(x2y – 1) × (3 – 2x2y)

= x2y (3 – 2x2y) – 1 (3 – 2x2y)

= 3x2y – 2x4y2 – 3 + 2x2y

= 5x2y – 2x4y2 – 3

Let us substitute the given values x = – 1 and y = – 2, then

= (x2y – 1) × (3 – 2x2y)

= [(-1)2 (-2) – 1] × [3 – 2 (-1)2 (-2)

= (-2 – 1) × (3 + 4)

= -3 × 7

= -21

Now,

= 5x2y – 2x4y2 – 3

= [-2 (-1)4 (-2)2 + 5 (-1)2 (2) – 3]

= – 8 – 10 – 3

= -21