Question

find the following product using a suitable identity (x+3/4y-4z)

Answer 1

HEY HERE IS YOUR ANSWER☺☺☺

We have to find the product of (x + 3/4y -4z)^2.

We can easily find the product using the identity :-
(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab +2bc + 2ac
where a = x , b = 3/4y and c = -4z

${(x + \frac{3}{4y} - 4z) }^{2} \\ \\ using \: \: the \: \: above \: \: identity \\ \\ {(x)}^{2} + ({ \frac{3}{4y} })^{2} + {( - 4z)}^{2} + 2 \times x \times \frac{3}{4y} + 2 \times \frac{3}{4y} \times ( - 4z) + 2 \times x \times ( - 4z) \\ \\ = {x}^{2} + \frac{9}{16 {y}^{2} } + {16z}^{2} + \frac{3x}{2y} + ( \frac{ - 6z}{y} ) + ( - 8xz) \\ \\ = {x}^{2} + \frac{9}{ {16y}^{2} } + {16z}^{2} + \frac{3x}{2y} - \frac{6z}{y} - 8xz$

HOPE MY ANSWER HELPS ☺☺☺
#AADI 93

Answer 2

Step-by-step explanation:

hope it helps

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