Math, asked by amishasiddesh, 7 months ago

Find the following product using suitable identities. Mention the
identities used
i) Square of (x+0.09)
ii) (0.2+0.3)(0.2−0.3)
iii)(2z²-9)(2z²+6)
iv) 10.5×9.5
v) 104²
vi)999²
vii) 61²-60²
viii) 113×102
plz don't spam answer with full steps plz solve these

Answers

Answered by chirag1026
0

Answer:

question

(a + b)2 = a2 + 2ab + b2

(a – b)2 = a2 – 2ab + b2

(a – b)(a + b) = a2 – b2

1) This question can be solved using the first identify

(x + 3) (x + 3)

=x2 + 6x + 9

2) This question can be solved using the first identify

(2y + 5) (2y + 5)

=4y2 + 20y + 25

3) This question can be solved using the second identify

(2a – 7) (2a – 7)

= 4a2 – 28a + 49

4) This question can be solved using the second identify

(3a-1/2)(3a-1/2)= 9a2 -3a+(1/4)

5) This question can be solved using the third identity

(1.1m – 0.4) (1.1m + 0.4)

= 1.21m2 – 0.16

5) This question can be solved using the third identity

(a2+ b2) (– a2+ b2)

= (b2 + a2 ) (b2 – a2)

= a4 - b4

6) This question can be solved using the third identity

(6x – 7) (6x + 7)

=36x2 - 49

7) This question can be solved using the third identity

= c2 - a2

8) This question can be solved using the first identity

[ (x/2)+(3y/4)] [ (x/2)+(3y/4)]

=(x2/4) + (9y2/16) +(3xy/4)

9) This question can be solved using second identity

= 49a2 – 126ab + 81b2

Answered by Aloneboi26
1

Answer:

Answer:

question

(a + b)2 = a2 + 2ab + b2

(a – b)2 = a2 – 2ab + b2

(a – b)(a + b) = a2 – b2

1) This question can be solved using the first identify

(x + 3) (x + 3)

=x2 + 6x + 9

2) This question can be solved using the first identify

(2y + 5) (2y + 5)

=4y2 + 20y + 25

3) This question can be solved using the second identify

(2a – 7) (2a – 7)

= 4a2 – 28a + 49

4) This question can be solved using the second identify

(3a-1/2)(3a-1/2)= 9a2 -3a+(1/4)

5) This question can be solved using the third identity

(1.1m – 0.4) (1.1m + 0.4)

= 1.21m2 – 0.16

5) This question can be solved using the third identity

(a2+ b2) (– a2+ b2)

= (b2 + a2 ) (b2 – a2)

= a4 - b4

6) This question can be solved using the third identity

(6x – 7) (6x + 7)

=36x2 - 49

7) This question can be solved using the third identity

= c2 - a2

8) This question can be solved using the first identity

[ (x/2)+(3y/4)] [ (x/2)+(3y/4)]

=(x2/4) + (9y2/16) +(3xy/4)

9) This question can be solved using second identity

= 49a2 – 126ab + 81b2

Similar questions