Question

find the following product (x/3a-y/4b)(x/3a+y/4b)​

Answer 1

Answer:

$\frac{ {x}^{2} }{9 {a}^{2} } - \frac{ {y}^{2} }{ 16{b}^{2} }$

Step-by-step explanation:

$( \frac{x}{3a } - \frac{y}{4b} )( \frac{x}{3a} + \frac{y}{4b} ) \\ = {( \: \frac{x}{ 3a} } \: )^{2} - {( \: \frac{y}{4b} } \: )^{2} \: \\ = \frac{ {x}^{2} }{ {(3a)}^{2} } - \frac{ {y}^{2} }{ {(4b)}^{2} } \\ = \frac{ {x}^{2} }{9 {a}^{2} } - \frac{ {y}^{2} }{ 16{b}^{2} }$