find the following products (-2×^2+×y-y^2)(3×+4y)
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Answer:
(-2x²+xy-y²)(3x+4y)
= 3x(-2x²+xy-y²)+4y(-2x²+xy-y²)
= -6x³+3x²y-3xy²-8x²y+4xy²-4y³
= -6x³-5x²y+xy²-4y³
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