find the following products [2/5a+1/7b](3a+4b-2)
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Answer:
After adding we get:
(3a−4b+4c)+(2a+3b−8c)+(a−6b+c)
=3a+2a+a−4b+3b−6b+4c−8c+c
=6a−7b−3c
Step-by-step explanation:
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