Question

Find the following products. (3/4x-y^2) (x+2/3y^2)​

Answer 1

Answer:

$\mathrm{\left(\frac{3}{4x-y^2}\right)\left(\frac{x+2}{3y^2}\right)=\frac{x+2}{y^2\left(4x-y^2\right)}}$

Step-by-step explanation:

$\mathrm{\left(\frac{3}{4x-y^2}\right)\left(\frac{x+2}{3y^2}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$\mathrm{=\frac{3}{4x-y^2}\cdot \frac{x+2}{3y^2}}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}$

$\mathrm{=\frac{3\left(x+2\right)}{\left(4x-y^2\right)\cdot \:3y^2}}$

$\mathrm{Cancel\:the\:common\:factor:}\:3$

$\mathrm{=\frac{x+2}{\left(4x-y^2\right)y^2}}$