Find the following products and verify the result, for x=-1,y=2. (x²-1/2x²)(1/3x²+1/x²)
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let us simplify the given expression = (x2y -
1) x (3 2x2y) = x2y (3 2x2y) - 1(3 - 2x2y) = 3x2y - 2x4y2-3 + 2x2y = 5x2y - 2x4y2 - 3 Let us substitute the given values x = 1 and y = -2, then = (x2y - 1) x (3 2x2y) = [(-1)2 (-2)-1] [32 (-1)2 (-2)= (-21) (3 + 4) = -3 x 7 = -21 Now, = 5x2y - 2x4y2-3 = [-2 (-1)4 (-2)2 + 5 (-1)2 (2)-3]=- 8-10 - 3 = -21
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