Question

Find the following products:
(i) (3a+2b) (-3a+2b)
(ii) (-xy+ak) (xy+ak)
don't post irrelevant answers otherwise reported​

Answer 1

$\sf{Answer}$

Step by step explanation:-

1) (3a+2b)(-3a+2b)

We can written as

(2b +3a ) ( 2b -3a)

It is in form of (a+b)(a-b)= a²-b²

Similarly

(2b+3a)(2b-3a) = (2b)² -(3a)²

4b² -9a²

So,the product of (3a+2b)(-3a+2b) is 4b²-9a²

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2) (-xy+ak)(xy+ak)

Similarily It can be written as

(ak-xy)(ak+xy)

It is in form of (a+b)(a-b) = a²-b²

So, (ak-xy)(ak+xy) = (ak)² -(xy)²

a²k²-x²y²

So product of (-xy+ak)(xy+ak) is a²k²-x²y²

Answer 2

Answer:

1. (3a+2b) (-3a+2b)

= 3a (-3a+2b) +2b (-3a+2b)

2.(-xy+ak) (xy +ak)

= - xy(-xy+ak) +ak(xy+ak)

Hope it's helpful for you dear...

Saranghae army ❣️