Question

find the following square by using identities and check answers by a actual multiplication (0.5x-0.3y)²​

Answer 1

Answer:

 $(0.5x-0.3y)^{2}$= $0.25x^{2} +0.09y^{2}-0.15xy$

Step-by-step explanation:

Given : $(0.5x-0.3y)^{2}$

To find : Value of given square equation.

Solution :

• The given equation is,  $(0.5x-0.3y)^{2}$
• We have to find the value of above equation by using identity.
• Now, we know the identity,

     $(a-b)^{2} = a^{2} +b^{2} -2ab$

• In the given equation, $a = 0.5x , b= 0.3y$  
• The given equation becomes,

     $(0.5x-0.3y)^{2}$ = $(0.5x)^{2} +(0.3y)^{2}-2*0.5x*0.3y$

                        = $0.25x^{2} +0.09y^{2}-0.15xy$

• ∴  $(0.5x-0.3y)^{2}$= $0.25x^{2} +0.09y^{2}-0.15xy$