Question

find the following square using the indentites
(7m-8a)^+(7m+8n)^​

Answer 1

Step-by-step explanation:

(7m−8n)

2

+(7m+8n)

2

Using,

(a−b)

2

=a

2

−2ab+b

2

(a+b)

2

=a

2

+2ab+b

2

we get,

=[(7m)

2

−2(7m)(8n)+(8n)

2

]+[(7m)

2

+2(7m)(8n)+(8n)

2

]

=(49m

2

−112mn+64n

2

)+(49m

2

+112mn+64n

2

)

=49m

2

−112mn+64n

2

+49m

2

+112mn+64n

2

=98m

2

+128n

2

Answer 2

Mark as brainliest and follow...

using

${(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab$

${(a + b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

${(7m - 8a)}^{2} = {(7m)}^{2} + {(8a)}^{2} - 2 \times 7m \times 8a$

${(7m + 8a)}^{2} = {(7m)}^{2} + {(8a)}^{2} + 2 \times 7m \times 8a$

Add above equ

$49 {m}^{2} + 64 {a}^{2} - 112ma + 49 {m}^{2} + 64 {a}^{2} + 112ma$

$98 {m}^{2} + 128 {a}^{2}$