Question

find the following squares
1=(0.5p+1.2q )^2
2= ( - 1/7b- 7n)^2 ​

Answer 1

Answer:

$1 = 0.25 {p}^{2} + 1.44 {q}^{2} + \frac{6}{5}pq$

$2 = \frac{1}{49 {b}^{2} } + 49 {n}^{2} + 2nb$