Question

Find the following Squares by using the identities
$(2 \div 3m + 3 \div 2n) {}^{2}$
​

Answer 1

Answer:

Hey!! Ur answer:

Using (a+b)²=a²+2ab+b²

we get,=(3/2m)²+2[(3/2m

(2/3n)]+(2/3n)²

=(9/4m²)+2mn+(4/9n²)

Step-by-step explanation:

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Answer 2

Given:-

$\:⇒ \tt \: ( \frac{2}{3}m + \frac{3}{2} n)^{2}$

Formula To Be Used:-

$⇒ \tt \: (a+b)^2=a^2+2ab+b^2$

Solution:-

$⇒ \tt \: ( \frac{2}{3}m)^{2}+2 [( \frac{2}{3}m) ( \frac{3}{2}n)]+( \frac{3}{2}n)^2$

$⇒ \tt( \frac{4}{9}m^2)+2mn+( \frac{9}{4}n^2)$

Hence, The Answer Is :-

${\small{\bold{\red{\underline{( \frac{4}{9}m^2)+2mn+( \frac{9}{4}n^2)}}}}}$