Question

find the following squares using identity. 1)(0.2x-0.5y)*2​

Answer 1

Answer:

${(0.2x - 0.5y)}^{2} \\ 0.04 {x}^{2} + 0.25 {y}^{2} - 2 \times 0.2x \times 0.5y \\ 0.04 {x}^{2} + 0.25 {y}^{2} - 0.20xy \\ hope \: it \: will \: help \: you$

Answer 2

Answer:

0.04x^2+0.25y^2-0.20xy is the answer

Step-by-step explanation:

by using identity (a-b) ^2=a^2+b^2+2ab

we get (0.2x)^2+(0.5y)^2-2×0.2x×0.5y

=0.04x^2+0.25y^2-0.20xy

hope it helps you