Question

find the following squares using the identities (0.7-0.8q)²​

Answer 1

Step-by-step explanation:

$\huge{ \underline{ \underline{ \mathfrak{ \blue{Answer:-}}}}}$

We know that,

$\huge{ \boxed{ \mathfrak{ \red{ {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} }}}}$

now,

$\tt \leadsto \: {(0.7 - 0.8q) \: }^{2}$

$\tt \leadsto \: {(0.7)}^{2} - 2(0.7)(0.8q) + {(0.8q)}^{2}$

$\tt \leadsto \: 0.49 - 1.12q + 0.64 {q}^{2}$

Answer 2

(0.7−0.8q)

2

\tt \leadsto \: {(0.7)}^{2} - 2(0.7)(0.8q) + {(0.8q)}^{2}⇝(0.7)

2

−2(0.7)(0.8q)+(0.8q)

2

\tt \leadsto \: 0.49 - 1.12q + 0.64 {q}^{2}⇝0.49−1.12q+0.64q

2