Find the following sums .
a) 1 + 2 + 3 + 4 + 5 + . . . . . . . . + 20
b) 8 + 16 + 24 + 32 + 40 + . . . . . . . . + 160
c) 5 + 13 + 21 + 29 + 37 + . . . . . . . + 157
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Answer:
a) a=1 , d=2-1=1 , n = 20
Sn=n/2[2a+(n-1)d]
Sn=20/2[2×1+(20-1)1]
Sn=10(2+19)
Sn=10(21)
Sn=210
Step-by-step explanation:
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